convert List<User> users to Page<User> in spring data mongo Pagination

The easiest way to do that is to simply create a page out of the existing list: new PageImpl<Foo>(listOfFoos, new PageRequest(page, size, sort), listOfFoos.size()) Hope it helps. Cheers, Eugen.

I tried the suggestion above but it seems that the totalElements, totalPages values are wrong. It displays all the results… numberOfElements value is not changing… while totalElements is varying.

lets say the number of results is 7.

current page is 1 and size is 5… “first”: true, “last”: false, “number”: 0, “numberOfElements”: 7, “size”: 5, “totalElements”: 7, “totalPages”: 2

current page is 2 and size is 5… “first”: false, “last”: false, “number”: 1, “numberOfElements”: 7, “size”: 5, “totalElements”: 12, “totalPages”: 3

current page is 3 and size is 5… “first”: false, “last”: false, “number”: 2, “numberOfElements”: 7, “size”: 5, “totalElements”: 17, “totalPages”: 4

current page is 4 and size is 5… “first”: false, “last”: false, “number”: 3, “numberOfElements”: 7, “size”: 5, “totalElements”: 22, “totalPages”: 5

It is really acting weird. below is the code used

    public Page<Ticket> getOwnedTicketList(Pageable pageable) throws IOException {
        User user = getCurrentUser();
        List<Ticket> tickets = m_ticketRepository.getTicketsOwned(user);
        Page<Ticket> page = new PageImpl<>(tickets,
                new PageRequest(pageable.getPageNumber(), pageable.getPageSize(), pageable.getSort()),
                tickets.size());
        return page;
    }

Thanks