[Question]What's the meaning of "The link 'xxx' force detached. Code: publisher(linkxxx). Details: AmqpMessagePublisher.IdleTimerExpired: Idle timeout: 00:10:00"

Library name and version

Microsoft.Azure.ServiceBus 5.0.0

Query/Question

Hi, azure-sdk-for-net friends

We use Azure service bus and recently we got a error message which need your help to understand better. thank you.

The error message like this:

Failed to send message to Service Bus due to exception: 
The link 'G4:9962303:88e1bcd9-360e-47ee-9625-3fb0286a4c2d;28:57:58:source(address:*outTopicAddress*):*outTopicName*' 

**is force detached**. Code: publisher(link2207). Details: AmqpMessagePublisher.IdleTimerExpired: Idle timeout: 00:10:00**., 

stack:   
   at Microsoft.Azure.ServiceBus.Core.MessageSender.OnSendAsync(IList`1 messageList)
   at Microsoft.Azure.ServiceBus.RetryPolicy.RunOperation(Func`1 operation, TimeSpan operationTimeout)
   at Microsoft.Azure.ServiceBus.RetryPolicy.RunOperation(Func`1 operation, TimeSpan operationTimeout)
   at Microsoft.Azure.ServiceBus.Core.MessageSender.SendAsync(IList`1 messageList)

// delete some stack message

I searched and found this page https://docs.microsoft.com/en-us/azure/service-bus-messaging/service-bus-amqp-troubleshoot#link-is-closed

It tell me that the error is a standard behaviors, but I’m still confused. The troubleshoot say

You can avoid them by making send/receive calls on the connection/link, which automatically recreates the connection/link.

At first, I thought the exception is only a “warning”, service bus will send message successfully for me, but then I realized as the exception throw out, I have to retry by myself and then the message will send successfully.

I’m confused, as this exception can avoid after retry(Do I understand right?), why need customer code do that rather than handle the exception inside service bus sdk?

What’s the meaning when exception The link 'xxx' force detached. Code: publisher(linkxxx). Details: AmqpMessagePublisher.IdleTimerExpired happen, does it means something wrong in my code, and what should I do to avoid this kind of exception or just retry is enough?

Thanks for your help!